Not so. I supplied this version earlier:

int array[] = {1, 2, 3, 4, 5};

for (int i = 0; i < 5; i++)
{
        int num = array[i];
        printf("%d", num);
        for (int i = 0; i < 5; i++)
                printf("%d", i * num);
}

On Saturday, Aug 30, 2003, at 15:19 America/New_York, Rasmus Lerdorf wrote:

It was based on the for construct from C and works exactly the same way.

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