Vadim Fedorenko wrote:

> > +/**
> > + * idpf_ptp_read_src_clk_reg_direct - Read directly the main timer value
> > + * @adapter: Driver specific private structure
> > + * @sts: Optional parameter for holding a pair of system timestamps from
> > + *  the system clock. Will be ignored when NULL is given.
> > + *
> > + * Return: the device clock time on success, -errno otherwise.
> > + */
> > +static u64 idpf_ptp_read_src_clk_reg_direct(struct idpf_adapter *adapter,
> > +                                       struct ptp_system_timestamp *sts)
> > +{
> > +   struct idpf_ptp *ptp = adapter->ptp;
> > +   u32 hi, lo;
> > +
> > +   /* Read the system timestamp pre PHC read */
> > +   ptp_read_system_prets(sts);
> > +
> > +   idpf_ptp_enable_shtime(adapter);
> > +   lo = readl(ptp->dev_clk_regs.dev_clk_ns_l);
> > +
> > +   /* Read the system timestamp post PHC read */
> > +   ptp_read_system_postts(sts);
> > +
> > +   hi = readl(ptp->dev_clk_regs.dev_clk_ns_h);
> > +
> > +   return ((u64)hi << 32) | lo;
> > +}
> 
> Am I right that idpf_ptp_enable_shtime() "freezes" the time in clk
> registers and you can be sure that no changes will happen while you are
> doing 2 transactions? If yes, then what does unfreeze it? Or does it
> just copy new values to the registers and they will stay until the next
> command?
Yep, these are shadow registers.

I guess they remain until overwritten on the next latch.

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