From: Paulo Zanoni <paulo.r.zan...@intel.com>
The current code was checking if all bits of "val" were enabled and
DE_PCH_EVENT_IVB was disabled. The new code doesn't care about the
state of DE_PCH_EVENT_IVB: it just checks if everything else is 1.
The goal is that future patches may completely disable interrupts, and
the LCPLL-disabling code shouldn't care about the state of
DE_PCH_EVENT_IVB.
Signed-off-by: Paulo Zanoni <paulo.r.zan...@intel.com>
---
drivers/gpu/drm/i915/intel_display.c | 2 +-
1 file changed, 1 insertion(+), 1 deletion(-)
diff --git a/drivers/gpu/drm/i915/intel_display.c
b/drivers/gpu/drm/i915/intel_display.c
index 846f2de..95e8831 100644
--- a/drivers/gpu/drm/i915/intel_display.c
+++ b/drivers/gpu/drm/i915/intel_display.c
@@ -6499,7 +6499,7 @@ static void assert_can_disable_lcpll(struct
drm_i915_private *dev_priv)
spin_lock_irqsave(&dev_priv->irq_lock, irqflags);
val = I915_READ(DEIMR);
- WARN((val & ~DE_PCH_EVENT_IVB) != val,
+ WARN((val | DE_PCH_EVENT_IVB) != 0xffffffff,
"Unexpected DEIMR bits enabled: 0x%x\n", val);
val = I915_READ(SDEIMR);
WARN((val | SDE_HOTPLUG_MASK_CPT) != 0xffffffff,
--
1.8.3.1
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