On Wed, 06 Jan 2010 01:42:48 +0100 Richard Riley <[email protected]> wrote:
RR> Ted Zlatanov <[email protected]> writes: >> Let's debug it. Run the following in a clean (emacs -q) instance: >> >> (require 'epa-file) >> (require 'auth-source) >> (require 'cl) >> (epa-file-enable) >> (setq auth-source-debug t ; use `message' to log messages >> epa-file-cache-passphrase-for-symmetric-encryption t >> auth-sources '((:source "~/.authinfo.gpg" :host t :protocol t))) >> (auth-source-user-or-password "login" "richardriley.net" "imap") >> >> What does the last call return (should be your login name)? What's in >> *Messages*? RR> It returns my login name ok. RR> *Messages* just has RR> auth-source-user-or-password: found (login)=(shamrock) for richardriley.net (imap) RR> "shamrock" RR> I also got prompted for a symmetric password to unlock the authinfo.gpg RR> Note that my login name for the remote host is, in this case, the same RR> as my local login id. If this works, it should work for all other IMAP cases as well. Look at nnimap.el, it has the same call in nnimap-open-connection. Can you try the auth-source-user-or-password call inside your regular sessions (instead of `emacs -q'), where auth-source.el doesn't work for you? Is there something you see that might hint what the problem is? Ted _______________________________________________ info-gnus-english mailing list [email protected] http://lists.gnu.org/mailman/listinfo/info-gnus-english
