On Wed, Feb 27, 2002 at 07:10:08PM +0530, Sandip Bhattacharya wrote:
| "st1" in "Method" is just a *local-variable* where a memory location is stored -
I am not sure if I still get it. Following is the Method:
private void Method(Stack st1,Stack st2) {
st2.push(new Integer(100));
st1 = st2;
System.out.println("st1 has: "+st1);
System.out.println("st2 has: "+st2);
}
The Method() gets st1, and st2 as parameters to the method. Since in
Java, we have parameters passed by reference, st2.push() is able to
modify st2. Now if I had st1.push(), then st1 would have been modified
and the effect would be seen in the main().
| initially this has the memory address of main:st1 and later on
| overwritten by the memory address of st2 or main:st2.
This is true. st1 is overwritten by memory address of st2 or main:st2.
So why doesn't it retain the assignment after it returns from Method()?
I guess, the OP wanted to know that.
chyrag.
--
Chirag Kantharia, symonds.net/~chyrag/
Linux scrooge 2.4.17 #1 Wed Jan 16 17:07:25 IST 2002 i686 unknown
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