Okay found out what to do, however not sure if there are some more
efficient method.
while read line
do
domain=`echo $line | cut -d" " -f1`
echo $domain >> FirstColumn.txt
done < input.txt
cat FirstColumn.txt | sort -u > unique.txt
mv unique.txt FirstColumn.txt
while read line
do
grep $line input.txt | cut -d" " -f3 | sed ':a;N;$!ba;s/\n/ | /g'
done < FirstColumn.txt
On Thu, Oct 9, 2014 at 8:49 AM, Balasubramaniam Natarajan <
bala150...@gmail.com> wrote:
> Oops sorry the input file looks like this.
>
> Bala -> 54;
> Bala -> 57
> Bala -> 56;
> Bala -> 60
> Name -> 64
> Name -> 67
> Name -> 67
> Name -> 70
> Super -> 78
> First -> 60
> First -> 29
>
> On Thu, Oct 9, 2014 at 8:44 AM, Balasubramaniam Natarajan <
> bala150...@gmail.com> wrote:
>
>> Hi
>>
>> I have a question of how to print the longest line in bash scripting ?
>> Most appropriate would be to search for longest dictionary value.
>>
>> *Input file contains*
>> Bala -> 54; 56; 57
>> Bala -> 54; 57
>> Bala -> 56; 57
>> Bala -> 54; 56; 57;60
>> Name -> 64; 66; 67
>> Name -> 64; 67
>> Name -> 66; 67
>> Name -> 64; 66; 67;60
>> Super -> 78
>> First -> 29, 60
>> First -> 29
>>
>> *Output should be*
>> Bala -> 54; 56; 57;60
>> Name -> 64; 66; 67;60
>> Super -> 78
>> First -> 29, 60
>>
>> --
>> Regards,
>> Balasubramaniam Natarajan
>> http://blog.etutorshop.com
>>
>
>
>
> --
> Regards,
> Balasubramaniam Natarajan
> http://blog.etutorshop.com
>
--
Regards,
Balasubramaniam Natarajan
http://blog.etutorshop.com
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