On Thursday 14 May 2009 19:02:56 Ratul Bhadury wrote: > Hello all, > > I've been trying to achieve something using Antlr v3, but have been > struggling for a while now, and think its now time to ask the help of more > experienced users, hence this mail. > > What I basically want to achieve is a simple parser which will accept lines > of the nature: > > sec = <keyword> > > I want any whitespace (spaces and tabs) before the '=' sign to be ignored, > but any spaces after '=' to be included in what will be regarded as the > keyword. Therefore: > sec= hello -> is valid > sec =hello people -> is valid > sec = hello -> is valid > se= hello -> is rejected
something like this? (this read only one clause), KEYWORD includes the whitespace at the beginning, but not at the end. grammar Key; start : clause EOF; clause : SECURITY KEYWORD WS* ; fragment WS : ' ' | '\t'; fragment NUMBER : ('0' .. '9')+; fragment WORD : ('a' .. 'z')+; SECURITY : ('S'|'s')('E'|'e')('C'|'c') WS* '=' ; KEYWORD : WS* (WORD | NUMBER); cheers, Michael List: http://www.antlr.org/mailman/listinfo/antlr-interest Unsubscribe: http://www.antlr.org/mailman/options/antlr-interest/your-email-address --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "il-antlr-interest" group. To post to this group, send email to il-antlr-interest@googlegroups.com To unsubscribe from this group, send email to il-antlr-interest+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/il-antlr-interest?hl=en -~----------~----~----~----~------~----~------~--~---