The tricky bit here is:
the UUID consists of a timestamp part and a machine specific part,
and, with mainframes, this machine specific part must contain the CPU
serial number
and the LPAR number. Otherwise the UUIDs will not be unique accross
different LPARs
on the same machine.
To build UUIDs like this, you need some callable service (I don't recall
the name, maybe CSRSI).
I wrote a C solution to do this in 2007 ca. for a customer of mine;
don't know if I will recall the details. If you want, you can write me
offline mail to discuss this (including the communication with COBOL),
Kind regards
Bernd
Am 31.10.2019 um 22:16 schrieb Charles Mills:
Are you up for building a C++ program that you could call from COBOL?
https://github.com/graeme-hill/crossguid/blob/master/src/guid.cpp
(Around line 160 there is a bunch of code that is ASCII-specific and not
commented as such. Easy to convert, but sloppy IMHO.)
Charles
-----Original Message-----
From: IBM Mainframe Discussion List [mailto:IBM-MAIN@LISTSERV.UA.EDU] On Behalf
Of Cameron Conacher
Sent: Thursday, October 31, 2019 12:40 PM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: How can I generate a UUID in a z/OS COBOL Program
Hello folks,
I Have done some googling, and I found something called GETITXUID.
I think this might satisfy my needs.
Has anyone used this? Or know of a more appropriate way to derive a UUID?
Can I just code CALL GETITXUID()?
I just want to be able to generate a UUID from inside a COBOL program
running in z/OS.
It might be a CICS/COBOL program or it might be a batch COBOL program, if
that makes any difference here.
Thanks
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