On Mon, Mar 16, 2015 at 5:31 PM, Charles Mills <[email protected]> wrote: > I don't really know but my logic goes like this: > > You can only turn JCSBAUTH back on if you are key 0, otherwise you will S0C4. > So you could set key 0, and then turn JSCBAUTH off, "do stuff," and then turn > it back on again -- but if you are going to run for any length of time "doing > stuff" in key 0 you might just as well leave JSCBAUTH on, and if on the other > hand you are going to go to user key, you are stuck there once you turn > JSCBAUTH off. > > Does that make sense? > > Charles
Charles, I just had a thought (and it's lonely). You start off APF authorized, key 8 as a "normal" APF program. You want to run program "B" from the STEPLIB, but without APF authorization. Perhaps the simplest way is to use SYNCHX something like: LOAD EP=B ST R0,EPA_B MODESET KEY=ZERO USING PSA,0 L R3,PSATOLD MY TCB USING TCB,R3 L R3,TCBJSCB GET JSCB ADDRESS DROP R3 ICM R3,B'1000',=X'00' CLEAR HIGH BYTE USING IEZJSCB,R3 NI JSCBOPTS,255-JSCBAUTH NOT APF L R15,EPA_B SYNCHX (15) INVOKES PROGRAM B IN TCB KEY OI JSCBOPTS,JSCBAUTH RESTORE APF AUTHORIZATION MODESET KEY=NZERO The SYNCHX is the magic which allows your code to stay key 0 while invoking the other program "in line" in key 8. When the program returns, your code is still key 0. At which point you restore APF authorization and continue on. -- If you sent twitter messages while exploring, are you on a textpedition? He's about as useful as a wax frying pan. 10 to the 12th power microphones = 1 Megaphone Maranatha! <>< John McKown ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [email protected] with the message: INFO IBM-MAIN
