Ignore the bytes.  In the EAV region, you get 53 groups of 21 cylinders for
every 1113 cylinders.

On Tue, Sep 17, 2013 at 11:29 AM, Grantham, Charles
<[email protected]>wrote:

> Thanks for the response.  I'm still a little confused by the 21 thing.  By
> my calculations 21*47,619,047 yields 999,999,987.
>
> The 8192 block size looks like a nice bit map for 65536; 65536/8 is 8192,
> so the first area fits nice into a bitmap of 8K.  Also when the theoretical
> limit of 255tb (268,434,453 cyl) and divid it by 8192, the result is 7FFF +
> a little, or a nice half word.  The current limit of 262,668 cyl on a bit
> map bases would fit nicely into 3+, 8192 blocks plus the original bit map
> for the first 65520 tracks or four total; (262,668-65520)/(8*8192) =
> 3.008+.  All of this with the assumption that allocation is in 21 bit
> chunks.
>
> OK, my brain hurts.
>
> The CA sizes makes a lot of sense to me.  315 (21*15) does yield some nice
> number for CAs; (1,3,5,7,9,15).  IMHO, a CA larger than 15 tracks doesn't
> make a lot of sense and that really opens up the use of the 000 of the CCW
> (CCCC000H) for EVA cylinder values.
>
> Hmmm.  In a world of powers of two, this is a interesting venture.
>
> Chip Grantham
> Sr. Software Engineer
> Syncsort Incorporated
> P: 201-882-8337  |  C: TBD  |   F: 201-573-5176
> E: [email protected]
> www.syncsort.com
>
> INTEGRATING BIG DATA… SMARTER
>
> -----Original Message-----
> From: IBM Mainframe Discussion List [mailto:[email protected]] On
> Behalf Of John Chase
> Sent: Monday, September 16, 2013 7:58 AM
> To: [email protected]
> Subject: Re: Makes you go hmmmm, EVA MSU of 21 Cyls
>
> On Thu, 12 Sep 2013 09:13:39 -0500, Chip Grantham wrote:
>
> >I've finally taken the time to try to understand the numbers behind the
> way EAVs were implemented.  I found a great discussion in the redbook "z/OS
> v1.12 Implimentation"  SG24-7853-00 manual, chapter 20.  Any time spend you
> happen to spend here is worth it. (not unlike all redbooks).   Thanks to
> those that wrote it.
> >
> >I did happen into a segment that makes me go hmmm.  20.4.3 Multicylinder
> unit section says the 21-cylinder value for the MCU is derived from being
> the smallest unit that can map out the largest possible EAV and stay within
> the index architecture (with a block size of 8192), as follows:
> >* It is also a value that divides evenly into the 1 GB storage segments
> >of an IBM DS8000,
> >* These 1 GB segments are the allocation unit in the IBM DS8000 and are
> equivalent to 1,113 cylinders.
> >
> >I'm sure the "index architecture" references the index vtoc architecture,
> which has always been a curious archeture to me.  Has this design ever been
> made open?  Just curious as to why it made 21 the magic number?
> >
> >I also ran into a math issue when I divided 21 into 1GB (or
> 1,073,741,824/21 = 51,130,563.0476...).  I suspect that's because the 1GB
> storage segment is a number used in the DS8000 degisn, and its really close
> to the 1GB value. Wondering if that's true or some other reason.
>
> IIRC, when discussing disk storage, "the industry" uses the decimal
> meanings of KB, MB, GB, etc.  Thus, a 1GB disk allocation would be
> 1,000,000,000 bytes, which divided by 21 yields 47,619,047.
>
>     -jc-
>
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-- 
Mike A Schwab, Springfield IL USA
Where do Forest Rangers go to get away from it all?

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