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- KB

------- Original Message -------
On Thursday, November 24th, 2022 at 12:59 AM, Sri h Kolusu <[email protected]> 
wrote:


> > > How do I calculate the amount of space a ____ dataset needs?
> 
> 
> A 3390-n device has a capacity of 56,664 bytes per track, of which 55,996 
> bytes are accessible by applications programmers. The largest blocksize you 
> can define is 32,760, which is good for tapes,but it is mere waste on DASD, 
> as 55,996 - 32760 = 23,236 bytes left over, and because tracks can't be 
> shared between other files, that leftover space would just be wasted. So, 
> 55,996/2 = 27,998, which is half-track blocking, the most space-efficient 
> blocksize to use on 3390's.If you have 3380 device types in your shop, the 
> maximum half-track blocksize is 23,476.
> 
> To calculate the most efficient blocksize to use: Optimal blocksize = 
> INTEGER(half-track-blocksize/LRECL)*LRECL
> 
> Assuming LRECL=500, so the optimal blocksize will be
> 
> Integer(27,998/500) is 55
> 
> 55 multiplied by lrecl(500) gives you 27500 which is the optimum blksize.
> 
> On a 3390, the best blocksize for a QSAM (Queued Sequential Access Mode) file 
> of record length 500 is 27,500.This will allow 55 records per block, or 110 
> records per track, or 1650 records per cylinder (cylinders are 15 tracks).
> 
> Assuming your volume of records e is 10,000, you can fit that data in less 
> than 7 cylinders(10,000/1650 = 6.06 rounded to 7)
> 
> We allocate the primary space as 7 cylinders. Now the secondary space 
> allocation is 20% of primary space which in this case is 7 * 0.2 = 1.4 
> rounded to 2
> 
> So, your space allocation for a dataset of lrecl 500 and a volume of 10,000 
> records would be
> 
> SPACE=(CYL,(7,2),RLSE)
> 
> Thanks,
> Kolusu
> 
> 
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