https://en.wikipedia.org/wiki/Euler%27s_totient_function

Sent from my iPad

> On 23 Aug 2022, at 23:45, Bob Bridges <robhbrid...@gmail.com> wrote:
> 
> Comment from another knowledgeable cove:
> 
> "In number theory, Euler's totient function counts the positive integers up 
> to a given integer n that are relatively prime to n. It is written using the 
> Greek letter phi as φ(n) or ϕ(n), and may also be called Euler's phi 
> function. In other words, it is the number of integers k in the range 1 ≤ k ≤ 
> n for which the greatest common divisor gcd(n, k) is equal to 1. The integers 
> k of this form are sometimes referred to as totatives of n."
> 
> First of all, yeah, "relatively prime", not "mutually prime" as I wrote 
> below.  It didn't seem quite right even at the time, though I suppose it was 
> clear enough.
> 
> So "(a, 26) = 1", I guess, is just another way of specifying why φ(26) is 12. 
>  I can take up the chapter again, now.
> 
> ---
> Bob Bridges, robhbrid...@gmail.com, cell 336 382-7313
> 
> /* Canada could have had the culture of France, the entrepreneurial spirit of 
> the US and the British tradition of tolerance.  Instead it got the culture of 
> the US, the entrepreneurial spirit of Britain and the French tradition of 
> tolerance. */
> 
> -----Original Message-----
> From: robhbrid...@gmail.com <robhbrid...@gmail.com> 
> Sent: Tuesday, August 23, 2022 17:12
> 
> Ah, so "(a, 26) = 1" simply states what I had already figured out, that there 
> must be no common factors between them.  (Not counting 1 itself, of course.)  
> I think I read once that another way of saying that is "<a> and 26 are 
> mutually prime".  Thanks, Horacio.
> 
> I'm thinking that in one sense there are actually an infinite number of 
> values that will work for <a>, but once you get to 26 and past they're simply 
> repeating previous values.  For instance, if you use 3 (and I'll pretend b=0 
> just for simplicity here) then the ciphertext numbers are 3, 6, 9, 12, 15, 
> 18, 21, 24, 1, 4, 7, 10, 13, 16, 19, 22, 25, 2, 5, 8, 11, 14, 17, 20, 23, 26. 
>  I could also use a=29, 55, 81 and so on, but the ciphertext sequence is 
> identical so there's no point.
> 
> -----Original Message-----
> From: IBM Mainframe Discussion List <IBM-MAIN@LISTSERV.UA.EDU> On Behalf Of 
> Horacio Luis Villa
> Sent: Tuesday, August 23, 2022 17:01
> 
> (m,n) is the great common divisor between m and n.
> Can't tell what phi(26)=12 is, but I would say is something like "there are
> 12 coprimes among the 26 first natural numbers".
> 
> ________________________________
> De: IBM Mainframe Discussion List <IBM-MAIN@LISTSERV.UA.EDU> en nombre de Bob 
> Bridges <robhbrid...@gmail.com>
> Enviado: martes, 23 de agosto de 2022 17:50
> 
> I got to talking with a church friend about encryption, and at lunch 
> yesterday he lent me a book on number theory that has a chapter on asymmetric 
> encryption.  Cryptography has long been a hobby of mine, but it's only 
> recently that I came to understand a little of how asymmetric encryption can 
> work.
> 
> The chapter I'm perusing will get into asymmetric encryption eventually, but 
> it's starting with simple rotational ciphers.  Expanding on the simple 
> rotation, it then talks about something it calls "affine transformations", 
> which introduce an additional term into the formula used to encrypt or 
> decrypt the text:
> 
>  C ≡ <a>P+<b> (mod 26)     0 ≤ C ≤ 25
> 
> ...where, it specifies, "(a, 26) = 1".  Here's where I pause:  What operation 
> is indicated by "(m, n)"?
> 
> It goes on to say that for 26 letters in the cipher, "there are ф(26) = 12 
> choices for <a>".  I can see that <a> and 26 must have no factors in common 
> for this to work, and without actually working out how many choices there are 
> I can easily believe the answer is 12, but what function is implied by phi?
> 
> ----------------------------------------------------------------------
> For IBM-MAIN subscribe / signoff / archive access instructions,
> send email to lists...@listserv.ua.edu with the message: INFO IBM-MAIN

----------------------------------------------------------------------
For IBM-MAIN subscribe / signoff / archive access instructions,
send email to lists...@listserv.ua.edu with the message: INFO IBM-MAIN

Reply via email to