Is there a tactical that shows that a term is equal to the same term with an added abstraction, for example:
|- ( f:(num->bool) ) n <=> (\x:num. f:(num->bool) ) n Or even more simply |- f:(num->bool) <=> (\x:num. f:(num->bool) ) ------------------------------------------------------------------------------ Check out the vibrant tech community on one of the world's most engaging tech sites, Slashdot.org! http://sdm.link/slashdot _______________________________________________ hol-info mailing list hol-info@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/hol-info
