Re: Dropping "call" operator?

[Stefan Monnier via Users list for the GNU implementation of make]

> Addendum, yes, directly via:
>
> define a b c
> ...
> endef
>
> as well as with embedded comma:
>
> define a b c,
> ...
> endef
>
> These can be referenced via $(a b c) and $(a b c,).

Eww!


        Stefan