On Wed, 2023-06-21 at 11:55 -0400, Brian J. Murrell wrote: > On Wed, 2023-06-21 at 11:47 -0400, Paul Smith wrote: > > On Wed, 2023-06-21 at 08:31 -0700, Kaz Kylheku wrote: > > > If I just have this: > > > > > > IMPORTANT_VAR := $(shell sh -c "echo calculate; echo executed > > > 1>&2") > > > > > > and do "make IMPORTANT_VAR=alternative", I still see "executed" > > > on standard output. > > > > IMO that is a bug and it should be reported as such on Savannah. > > Is it? Isn't the functionality of not overriding a variable value > set on the make command line with a value in the Makefile what the ?= > assignment operator is for?
No. Variables assigned on the command line always take precedence over values set in the makefile, regardless of which assignment operator is used. This is easy to see: $ cat Makefile V ?= foo all: ; @echo '$(V)' $ make foo $ make V=bar bar The only way to have a variable in a makefile take precedence over a command line variable is by adding the override statement. https://www.gnu.org/software/make/manual/html_node/Overriding.html
