On Mon, 2016-10-10 at 20:45 -0700, Emmanuel Mayssat wrote: > > Also you don't escape dollar signs with backslashes inside make, > you > > escape them by writing two dollar signs "$$". > > It turns out I was trying to escape the $(P) and $$(P) did not expend > to anything
Right, because $$(P) expands to the static string '$(P)' not a reference to a variable, so that is what would be passed to the shell. > (but \$(P) did!). It will expand to the static string '\x' where "x" is each value in the loop. However the shell will ignore that backslash since it doesn't escape any interesting characters, so it's essentially a no-op in this case (but it could cause problems in other situations if used incorrectly). It's helpful to look very carefully at the output command line that make prints. That's what it's sending to the shell, so if that doesn't look right then you'll need to figure out why. _______________________________________________ Help-make mailing list Help-make@gnu.org https://lists.gnu.org/mailman/listinfo/help-make
