Makefiles are divided between make syntax and shell (recipe) syntax. Here
you're trying to use a shell command (echo) in a place that's not a recipe.
Replace it with $(warning ...) which is the make-syntax equivalent.
On Tue, Apr 5, 2016 at 9:24 AM, David Aldrich <david.aldr...@emea.nec.com>
wrote:
> Hi David
>
> Thanks for your answer to my question. I have one outstanding problem.
> Part of the makefile is now:
>
> ifeq ($(DISTRO),debian)
> verstr := $(ldd --version | head -1 | awk '{print $NF}')
> @echo glibc $(verstr) detected
> ifneq ($(call version_ge,$(verstr),2.22),TRUE)
> @echo "Warning: system glibc is incompatible with Zodiac so using
> glibc from OPEN_SOURCE_LIBS"
> GLIBC=$(OPEN_SOURCE_LIBS)/glibc/v2_22/
> GLIBC_FLAGS=
> -Wl,-rpath=${GLIBC}:${GLIBC}/math:${GLIBC}/elf:${GLIBC}/dlfcn:${GLIBC}/nss:${GLIBC}/nis:${GLIBC}/rt:${GLIBC}/resolv:${GLIBC}/crypt:${GLIBC}/n$
> endif
> endif
>
> For the first echo statement I get:
>
> Makefile:236: *** missing separator. Stop.
>
> Please can you suggest how I should correct that line?
>
> Best regards
>
> David
>
_______________________________________________
Help-make mailing list
Help-make@gnu.org
https://lists.gnu.org/mailman/listinfo/help-make
