On 05/26/2015 09:15 AM, David Boyce wrote:
BTW /usr/bin/env creates a redundant process here. The reason people
use /usr/bin/env to translate an execv() (does not use PATH) to an
execvp() (does). But GNU make uses execvp() already; try "make
SHELL=sh” to see that.
-David Boyce
Thanks. That's good to know.
On Tue, May 26, 2015 at 5:14 AM, Paul Smith <psm...@gnu.org> wrote:
On Mon, 2015-05-25 at 21:05 -0700, Afif Elghraoui wrote:
SHELL=/usr/bin/env sqlite3
.SHELLFLAGS=-init <(echo ".output $@") $(DB)
I get this error:
/bin/sh: 1: Syntax error: "(" unexpected
Makefile:13: recipe for target 'fq' failed
It looks like .SHELLFLAGS is evaluated with /bin/sh regardless of what
SHELL is set to. Is there any way I could evaluate them with bash?
You're missing the main point: the values of SHELL and SHELLFLAGS aren't
being evaluated by /bin/sh, or bash... they're not being evaluated by
any shell at all!
Fair enough. I guess I was further confused that my error message was
coming from /bin/sh.
The entire point of setting SHELL is you're choosing a shell that make
will invoke. Make does not use a shell to start the shell that you
requested: it invokes the shell you requested directly (using the exec()
system calls).
Got it.
The simplest way to do what you want is create a script (outside of
make) that will operate like this, then set SHELL in your makefile to
that script. You can use #!/bin/bash at the top of that script to
request it be run in bash, if you like.
That works out really well. My Makefile header became:
SHELL=./sqlite-wrapper.bash
# The DB variable is defined in the top-level Makefile
.SHELLFLAGS=$@ $(DB)
and the wrapper script is:
#!/bin/bash
sqlite3 -init <(cat sqliterc <(echo ".output $1")) $2 "$3"
I added here another functionality I needed. I'm very glad that it works
now.
Many thanks and regards
Afif
--
Afif Elghraoui
Laboratory for Pathogenesis of Clinical Tuberculosis Drug Resistance and
Persistence
San Diego State University
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