I thought I fixed it but I was incorrect. I reworked the rules and the
error is like this
Ambiguity detected.
Option 1,
A -> <Rule 43, tokens 226 .. 229>
B -> <Rule 41, tokens 226 .. 228>
A -> <Rule 43, tokens 226 .. 228>
B -> <Rule 41, tokens 226 .. 227>
A -> <Rule 44, tokens 226 .. 227>
C -> <Rule 45, tokens 226 .. 227>
D -> <Rule 52, tokens 226 .. 227>
E -> <Rule 175, tokens 226 .. 227>
'$' <tokens 226 .. 226>
VarName <tokens 227 .. 227>
C -> <Rule 45, tokens 228 .. 228>
D -> <Rule 53, tokens 228 .. 228>
F -> <Rule 55, tokens 228 .. 228>
G -> <Rule 59, tokens 228 .. 228>
'.' <tokens 228 .. 228>
C -> <Rule 45, tokens 229 .. 229>
D -> <Rule 46, tokens 229 .. 229>
H -> <Rule 79, tokens 229 .. 229>
I -> <Rule 81, tokens 229 .. 229>
Var -> <Rule 1065, tokens 229 .. 229>
VarFilter -> <Rule 1066, tokens 229 .. 229>
VAR <tokens 229 .. 229>
Option 2,
A -> <Rule 44, tokens 226 .. 229>
C -> <Rule 45, tokens 226 .. 229>
D -> <Rule 52, tokens 226 .. 229>
E -> <Rule 175, tokens 226 .. 229>
'$' <tokens 226 .. 226>
VarName -> <Rule 1025, tokens 227 .. 229>
VarName <tokens 227 .. 227>
'.' <tokens 228 .. 228>
Var -> <Rule 1065, tokens 229 .. 229>
VarFilter -> <Rule 1066, tokens 229 .. 229>
VAR <tokens 229 .. 229>
I notice they both start at A so maybe I can get it to use C and avoid B
A:
C %dprec 2
| B C %dprec 1
| B ',' C %dprec 1
When I compile and ran it I got no more ambiguity error. HOWEVER it seems
to ALWAYS take the B C path instead of plain C. The line i run is
h.i=$j.k
and my code output says `h (Tok .) i (Tok .)k
I'm missing `=$j` because it belongs to the i AST and I only print the
left. The `.k` should belong to the $j (see option 2 path). Var name is
basically `VarName: Var | VarName '.' Var`.
Since in my A rule I say C has a higher precedence why isn't it taking that
path? It seemed to fix the Ambiguity but doesn't seem to listen to the
dprec. I tried making the C rule last of the three and it didnt work.
Doesn't bison always shift when possible? why is it reducing? :(
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