On Sun, 9 Nov 2008, Nelson Ferreira wrote: > I have a very very simple parser and in 2.3 I could define some additional > functions using YYSTYPE just by including the generated header because it > defined: > > #if ! defined YYSTYPE && ! defined YYSTYPE_IS_DECLARED > typedef int YYSTYPE; > # define yystype YYSTYPE /* obsolescent; will be withdrawn */ > # define YYSTYPE_IS_DECLARED 1 > # define YYSTYPE_IS_TRIVIAL 1 > #endif > > > however, now in 2.4 this is what I get there: > > #if ! defined YYSTYPE && ! defined YYSTYPE_IS_DECLARED > > # define yystype YYSTYPE /* obsolescent; will be withdrawn */ > # define YYSTYPE_IS_DECLARED 1 > #endif > > This strikes me as a bug, specially because you actually define > YYSTYPE_IS_DECLARED to 1 without defining YYSTYPE.
Please show us a complete grammar file that causes this behavior. > I also tried defining YYSTYPE in the .y itself but it had absolutely no > influence in the generated .y. Please show us exactly what you did here too. Thanks. _______________________________________________ help-bison@gnu.org http://lists.gnu.org/mailman/listinfo/help-bison
