On 22 April 2012 19:11, TP <paratribulati...@free.fr> wrote: > Hello, > > I have a module where I have made several types as instances of the Show > typeclass. > > For debugging purpose, I would like to use the default implementation for Show > (the one obtained when using "deriving", which shows all the constructors). Is > there some option to do that, or have I to comment all the Show instances of > my code, and add "Show" in "deriving (...)" for each of my types? If this is > the only possibility, is there some script around here to do that > automatically?
Is there any particular reason you're *not* using the defaults? > > Thanks in advance, > > TP > > _______________________________________________ > Haskell-Cafe mailing list > Haskell-Cafe@haskell.org > http://www.haskell.org/mailman/listinfo/haskell-cafe -- Ivan Lazar Miljenovic ivan.miljeno...@gmail.com http://IvanMiljenovic.wordpress.com _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
