On Sat, 25 Dec 2010, gutti wrote:
this line works :
matrixfunction x y = liftMatrix2 (zipVectorWith(\a1 a2 -> if a2>=0 then a1 else
0)) x y
but when I use this line :
matrixfunction f x y = liftMatrix2 (zipVectorWith f) x y
how can / do I have to define f in a seperate line a way, that it works and
gives the same result ?
The same way you have literally replaced
(\a1 a2 -> if a2>=0 then a1 else 0)
by 'f' at the right hand side, you can use that phrase as argument to the
parameter 'f':
matrixfunction (\a1 a2 -> if a2>=0 then a1 else 0) x y
The lambda expression (\ ...) really is just a notation for a function.
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