On Wed, Mar 17, 2010 at 10:20:02PM -0700, Alexander Solla wrote: > > On Mar 17, 2010, at 9:56 PM, Alexander Solla wrote: > > >But your "spherical" points don't really form a basis in three- > >space, or even over all of two-space. > > I'll take this back. Lattitude and longitude is enough to "form a > basis" on R^2, by taking a basis for the surface of the sphere in > terms of latitude and longitude and projecting it stereographically. > So if you wanted to use the normalization idea, you could use the > stereographic projection formulas to turn a spherical point into a > Cartesian point. > > http://en.wikipedia.org/wiki/Stereographic_projection
Yes. I believe other projections can be used as well (orthographic, etc). -- Darrin Chandler | Phoenix BSD User Group | MetaBUG dwchand...@stilyagin.com | http://phxbug.org/ | http://metabug.org/ http://www.stilyagin.com/ | Daemons in the Desert | Global BUG Federation
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