ivan.miljenovic:
> On 24 February 2010 20:17, Magnus Therning <mag...@therning.org> wrote:
> > I often find that I do want an export list to reduce clutter in the
> > finished code, but for testing I'd like to expose everything in a
> > module. Is there a nice way to deal with this (using the C
> > pre-processor would not qualify as "nice" ;-)?
> > Maybe there's a switch that causes GHC to simply ignore the export
> > list of a module and export everything?
>
> If you start a function name with an underscore, it is "implicitly
> exported" by GHC (I can't find the actual documentation page at the
> moment however). Whilst it may not appear in the export list, you are
> still able to call it from outside the module.
Seriously?? Doesn't that break the module system?
So this should work?
Z.hs
module Z () where
_secret = "10"
M.hs
import Z
main = print _secret
$ runhaskell M.hs
M.hs:3:14: Not in scope: `_secret'
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