> The easiest solution is simply to define > > unionAll = nub . mergeAll > where > -- specialized definition of nub > nub = map head . groupBy (==) > >
Talking about the easiest solution, I guess this is a quite easy way of defining unionAll as well: http://gist.github.com/306782 I, of course, do not claim that it is more efficient or better. But I don't think it'd be rubbish :) -- Ozgur Akgun
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