Hi all
On 17 Dec 2009, at 14:22, Tom Schrijvers wrote:
class MyClass k where
type AssociatedType k :: *
Is there a way of requiring AssociatedType be of class Eq, say?
Have you tried:
{-# LANGUAGE TypeFamilies #-}
{-# LANGUAGE FlexibleContexts #-}
class Eq (AssociatedType k) => MyClass k where
type AssociatedType k :: *
I just got very excited about this. I'm supposed to be
setting a test, but this is far more interesting. I tried
this
> {-# LANGUAGE TypeFamilies, FlexibleContexts, EmptyDataDecls,
TypeOperators #-}
> module DDD where
> class (Diff (D f)) => Diff f where
> type D f
> plug :: D f x -> x -> f x
> newtype K a x = K a deriving Show
> data Void
> magic :: Void -> a
> magic x = x `seq` error "haha"
> instance Diff (K a) where
> type D (K a) = K Void
> plug (K c) x = magic c
> newtype I x = I x deriving Show
> instance Diff I where
> type D I = K ()
> plug (K ()) x = I x
> data (f :+: g) x = L (f x) | R (g x) deriving Show
> instance (Diff f, Diff g) => Diff (f :+: g) where
> type D (f :+: g) = D f :+: D g
> plug (L f') x = L (plug f' x)
> plug (R g') x = R (plug g' x)
> data (f :*: g) x = f x :& g x deriving Show
> instance (Diff f, Diff g) => Diff (f :*: g) where
> type D (f :*: g) = (D f :*: g) :+: (f :*: D g)
> plug (L (f' :& g)) x = plug f' x :& g
> plug (R (f :& g')) x = f :& plug g' x
But I got this message
[1 of 1] Compiling DDD ( DDD.lhs, interpreted )
DDD.lhs:5:2:
Cycle in class declarations (via superclasses):
DDD.lhs:(5,2)-(7,28): class (Diff (D f)) => Diff f where {
type family D f; }
Failed, modules loaded: none.
and now I have to go back to setting my class test.
Sorry for spam
Conor
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