satorisanitarium wrote:
>
> How to make a list of sublists out of a list, whether they be a list of
> numbers or a string.
>
Without recursion (with fold) starting from the tail of the input list:
foo n = foldr st [[]]
where
st x xss | x == n = [x]:xss
st x (xs:xss) = (x:xs):xss
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