On Tue, May 5, 2009 at 8:49 PM, Nico Rolle <nro...@web.de> wrote: > Hi everyone. > > I have a problem. > A function is recieving a lambda expression like this: > (\ x y -> x > y) > or like this > (\ x y z a -> (x > y) && (z < a) > > my problem is now i know i have a list filled with the parameters for > the lambda expression. > but how can i call that expression? > [parameters] is my list of parameters for the lambda expression. > lambda_ex is my lambda expression > > is there a function wich can do smth like that? > > lambda _ex (unfold_parameters parameters) >
Why not: lam1 = \[x, y] -> x > y lam2 = \[x, y, z, a] -> (x > y) && (z < a) doLam :: Ord a => ([a] -> Bool) -> [a] -> Bool doLam lam params = lam params So, this will work fine: doLam lam1 [1, 2] doLam lam2 [1,2,3,4] -- Victor Nazarov
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