Thanks. My question is whether it can call a function (say map) previously defined elsewhere in the program. Same goes for filter.
Tope On Fri, Feb 22, 2008 at 6:04 AM, Christian Maeder <[EMAIL PROTECTED]> wrote: > TOPE KAREM wrote: > > I know the following: > > > > [1] That the general form of conditional expression is: if > > *Boolean_expression* then /exp1/ else /exp2 > > /[2] That a conditional expression must always have both a then and an > > else expression. > > [3] That both /exp1/ and /exp2/ must have the same type, which is the > > type of the entire conditional expression. > > [4] That /exp1/ must be <true-value> and /exp2/ must be <false-value> > > > > Reference: Discrete Mathematics Using Computer by John O'Donnell and et > > al. (Second Edition) > > > > My question: Is it possible that exp1 and exp 2 be different function > > calls of another functions (separately) elsewhere within the same > program? > > Note: My Boolean_expression is Boolean > > My /exp1/ is a function call elsewhere within the same program > > (more like a subroutine) > > My /exp2/ is another function call also elsewhere within the > > same program. > > I'm not sure what you're asking, but exp1 and exp2 may have (the same) > function type: > > if <cond> then map else filter :: (Bool -> Bool) -> [Bool] -> [Bool] > > HTH Christian >
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