I'll have to trust you, because I cannot test it.
let x=(1:x); y=(1:y) in x==y .
I also cannot test this:
let x=(1:x); y=1:1:y in x==y
On Thu, 27 Dec 2007 17:29:12 +0200, Lennart Augustsson
<[EMAIL PROTECTED]> wrote:
One value. One "infinite" value.
On Dec 27, 2007 3:53 PM, Cristian Baboi <[EMAIL PROTECTED]> wrote:
On Thu, 27 Dec 2007 16:50:10 +0200, Lennart Augustsson
<[EMAIL PROTECTED]> wrote:
> Absolutly. Every expression in Haskell denotes a value.
> Now, we've not agreed what "value" means, but to me it is a value. :)
It is one value, or several ?
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