On Thu, Sep 20, 2007 at 05:20:46PM +0400, Victor Nazarov wrote: > I still can't remember how guards are treated in Haskell. Here is the > code snippet in question: > > foo a | a == 1 = 6 > foo a | a == 2 = 7 > foo a = 8 > > Would Haskell fall through to the third alternative if a is not equal > to 1 or 2. I know that this can be rewritten more sanely, but I just > consider guard behavior. What would be the value of (foo 3)?
8. It falls through if no guards in a rhs match. Stefan
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