On Thursday 26 July 2007, Jon Harrop wrote: > If you have a boolean-or expression: > > a || b > > will "a" be evaluated before "b" in Haskell as it is in other languages?
Yes. The definition of (||) is roughly True || b = True False || b = b Which de-sugars to (||) = \ a b -> case a of True -> True False -> b Which does exactly what you want. Jonathan Cast http://sourceforge.net/projects/fid-core http://sourceforge.net/projects/fid-emacs
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