At Fri, 05 Jan 2007 17:58:14 -0800, Jeremy Shaw wrote: > Because you never demand the value of any element in the list, Haskell > never bothers to calculate it. So you have a list that looks like: > > [ i, i - 1, (i - 1) - 1, ((i - 1) - 1 - 1), .. ]
I should clarify that this is the list that will be built by: > makelist i = i : (makelist (i-1)) [1..] will be building something like: > [ 1, succ 1, succ (succ 1), succ (succ (succ 1)), ...] j. _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
