On 29/12/06, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
And if you don't want to think about it, this should make everything
clear:

My additions displayed below:

f :: A -> B -> C -> D
    f :: A -> (B -> (C -> D))
By right-associativity of f.
    f a :: B -> (C -> D)
    (f a) b :: C -> D
    ((f a) b) c :: d
s/d/D/

--
-David House, [EMAIL PROTECTED]
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