Neil Mitchell wrote:
Hi,
You could try Hoogle <URL: http://haskell.org/hoogle/ >,
though entering Int -> [Char] isn't very helpful,
A known "issue", Hoogle 4 will know about [Char] = String, and will
also be tweaked to give show first in this instance.
Thanks
Neil
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You can use show :: (Show a) => a -> String
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