Hi,
I tried to write function lexList by using an intermediate function
lisOfString as below:
module Lex where
lexList :: String -> [String]
lexList str = listOfString (lex str)
lexList [] =[]
listOfString :: [(String,String)] -> [String]
listOfString [(s1,s2)] = s1: listOfString (lex s2)
listOfString [("","")] = []
When I try function lisOfString as below, it runs forever (non-stop)
although I have the stop criteria for it ??
Lex> lisOfString ["test1","test2(test3)"]
Thanks in advance.
S.
On 6/17/06, Neil Mitchell <[EMAIL PROTECTED]> wrote:
> Hi
>
> On 6/18/06, Sara Kenedy <[EMAIL PROTECTED]> wrote:
> > Sorry, I am not clear at some point in your answer:
> >
> > 1) The function
> > lex :: String -> [(String,String)]
> > and
> > filter :: (a -> Bool) -> [a] -> [a]
> > So, I did not see how filter can use the list of tuple string of lex.
>
> You can write a function lexList, of type String -> [String], by
> repeatedly calling lex - its not too hard. Once you have this the
> filter will work.
>
> Thanks
>
> Neil
>
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