From the conclusion that both programs compute the same result it can be concluded that the fact that you have made use of a list comprehension has forced you to make a choice which should not matter, i.e. the order in which to place the generators. This should be apparent from your code.
My approach is such a situation is to "define your own generator" (assuming here that isSafe needs both its parameters): pl `x` ql = [ (p,q) | p <-pl, q <- ql] queens3 n = map reverse $ queens' n where queens' 0 = [[]] queens' k = [q:qs | (qs, q) <- queens' (k-1) `x` [1..n], isSafe q qs] isSafe try qs = not (try `elem` qs || sameDiag try qs) sameDiag try qs = any (\(colDist,q) -> abs (try - q) == colDist) $ zip [1..] qs Of course you can make more refined versions of `x`, which perform all kinds of fair enumeration, but that is not the main point here. It is the fact that the parameters to `x` are only evaluated once which matters here. Doaitse On Jan 29, 2013, at 10:25 , Junior White <efi...@gmail.com> wrote: > Hi Cafe, > I have two programs for the same problem "Eight queens problem", > the link is http://www.haskell.org/haskellwiki/99_questions/90_to_94. > My two grograms only has little difference, but the performance, this is > my solution: > > -- solution 1------------------------------------------------------------ > queens1 :: Int -> [[Int]] > > queens1 n = map reverse $ queens' n > > where queens' 0 = [[]] > > queens' k = [q:qs | q <- [1..n], qs <- queens' (k-1), isSafe > q qs] > isSafe try qs = not (try `elem` qs || sameDiag try qs) > > sameDiag try qs = any (λ(colDist, q) -> abs (try - q) == colDist) $ > zip [1..] qs > > -- solution 2-------------------------------------------------------------- > queens2 :: Int -> [[Int]] > > queens2 n = map reverse $ queens' n > > where queens' 0 = [[]] > > queens' k = [q:qs | qs <- queens' (k-1), q <- [1..n], isSafe > q qs] > isSafe try qs = not (try `elem` qs || sameDiag try qs) > > sameDiag try qs = any (λ(colDist,q) -> abs (try - q) == colDist) $ > zip [1..] qs > > the performance difference is: (set :set +s in ghci) > *Main> length (queens1 8) > 92 > (287.85 secs, 66177031160 bytes) > *Main> length (queens2 8) > 92 > (0.07 secs, 17047968 bytes) > *Main> > > The only different in the two program is in the first is "q <- [1..n], qs <- > queens' (k-1)," and the second is "qs <- queens' (k-1), q <- [1..n]". > > Does sequence in list comprehansion matter? And why? > _______________________________________________ > Haskell-Cafe mailing list > Haskell-Cafe@haskell.org > http://www.haskell.org/mailman/listinfo/haskell-cafe
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