The function > app1 f x = f >>= ($ x) or equivalently > app2 f x = join (f <*> pure x)
with type Monad m => m (a -> m b) -> a -> m b ? Hoogle did not help. JacquesPS: a nice point-free version would be appreciated as well. I can easily change app1 and app2 myself to point-free with enough applications of flip, . and $, but none of those are 'nice'.
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