On 12-08-15 03:20 AM, wren ng thornton wrote:
(forall a. P(a)) -> Q <=> exists a. (P(a) -> Q)
For example:
A. (forall p. p drinks) -> (everyone drinks)
B. exists p. ((p drinks) -> (everyone drinks))
In a recent poll, 100% of respondents think A true, 90% of them think B
paradoxical, and 40% of them have not heard of the Smullyan drinking
paradox.
Hehe!
http://www.vex.net/~trebla/weblog/any-all-some.html
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