Pritpal,
Remember this.-
http://lists.harbour-project.org/pipermail/harbour/2009-April/017872.html
Now you have this.-
#define hbqt_par_QIcon( n ) ( ( QIcon ) hb_parc( n ) )
#define hbqt_par_QString( n ) ( ( QString ) hb_parc( n ) )
/*
* QFont ()
* QFont ( const QString & family, int pointSize = -1, int weight = -1, bool
italic = false )
* QFont ( const QFont & font, QPaintDevice * pd )
* QFont ( const QFont & font )
*/
HB_FUNC( QT_QFONT )
{
if( HB_IS_STRING( 1 ) )
{
hb_retptr( ( QFont* ) new QFont() );
}
else
{
hb_retptr( ( QFont* ) new QFont( hbqt_par_QString( 1 ),
HB_ISNUM( 2 ) ? hb_parni( 2 ) : -1,
HB_ISNUM( 3 ) ? hb_parni( 3 ) : -1,
hb_parl( 4 ) ) );
}
}
Xavi
Pritpal Bedi escribió:
Thanks Przemek and Xavi
Przemyslaw Czerpak-2 wrote:
Not a 'const'. 'const' is only parameter attribute not type
which informs the compiler that given function will not change
passed value.
You have to convert it to QFont and then C++ will convert it to
QFont& following the function declaration.
Below it's self contain example which should help you in understanding
the C++ references.
If you think about it then you will find why C++ has to be such restricted
in type checking. Without it it will not be possible to compile most of
code.
best regards,
Przemek
#include <stdio.h>
void f( int & var )
{
var += 10;
}
int main( void )
{
int i = 5;
int * p = &i;
printf( "[%d]\n", i );
f( i );
printf( "[%d]\n", i );
printf( "[%d]\n", *p );
f( *p );
printf( "[%d]\n", *p );
return 0;
}
It has cleared my doubts.
I am worndering how I could not tested it like this or what
I was doing wrong. It is as simple as:
hbqt_par_QWebView( 1 )->setUrl( *hbqt_par_QUrl( 2 ) );
Regards
Pritpal Bedi
PS : This discovery (sighhhh) has forced me to rewrite hbqtgen.prg.
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