On Thursday, January 10, 2008, 17:33 Przemyslaw Czerpak <[EMAIL PROTECTED]> wrote:
PC> It's correct. ASCAN() uses EQUAL comparison not EXACTLY EQUAL comparison. That's clear. What I don't understand - how two objects can be EXACTLY EQUAL and in the same time NOT simply EQUAL. Regards, Alexander http://kresin.belgorod.su _______________________________________________ Harbour mailing list Harbour@harbour-project.org http://lists.harbour-project.org/mailman/listinfo/harbour