Mike Gran <spk...@yahoo.com> writes: > (quasiquote (sym unquote func)) > `(sym unquote func) > > Is this a valid use of unquote? > > I get that (cons 'a (list 'b 'c)) == (list 'a 'b 'c), but, I'm not sure > if unquote should be valid in that sort of construction.
As has already been pointed out, since ,foo is literally the same as (unquote foo), (a . (unquote foo)) = (a unquote foo) has to be literally the same as (a . ,foo). This is actually a source of one of my favourite Scheme implementation bugs (favourite since it is common, subtle, but harmless) Try a few scheme implementations and see how many error on `#(1 2 3 unquote foo) because of implementing vector quasiquotation under the hood as list quasiquotation. -- Ian Price -- shift-reset.com "Programming is like pinball. The reward for doing it well is the opportunity to do it again" - from "The Wizardy Compiled"
