Hello,
I'm trying to write an expression that will be true if either one of two files
are present. The expression must return true if either ntldr or bootmgr is
present on the first partition of the first drive. If either one is present I
want to boot to windows on that partition.
So I tried:
if [ -e (hd0,msdos1)/ntldr -o -e (hd0,msdos1)/bootmgr ] ; then
#do stuff to boot windows
This works great if ntldr is present. But if ntldr is NOT present, and bootmgr
is present, then the test fails. So I reversed the order:
if [ -e (hd0,msdos1)/bootmgr -o -e (hd0,msdos1)/ntldr ] ; then
#do stuff to boot windows
Which works if bootmgr is present, but not for ntldr.
In other words, it appears that combining expressions with or operation does
not work. Only the first operand is used. Is the or operation implemented?
I guess I can change separate the expression into two separate if statements.
Thanks,
Kent Loving
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