On Monday 21 October 2002 7:56 pm, you wrote:
> En op 21 oktober 2002 sprak Gareth McCaughan:
> > I'm feeling very dim. What's wrong with the much simpler
> >
> > sub subst { (my $a=shift) =~ s/\$\d+/eval$&/eg; $a; }
>
> You have to replace '$1' by the actual value of $1. If you try that
> with a regex, $1 is changed. In your case, $1 (and $2, $3 etc.) is
> undefined.
D'oh, of course.
What's particularly embarrassing is that I *tested* it.
How could that possibly have worked, I hear you ask?
Simple. Excerpt from my little test program:
print subst("$2, $1 and $3"), "\n";
Aieeee! :-)
--
g
