Given this code (which I know is not “correct”):
func BenchmarkOrders(b *testing.B) {
var ob = orderBook{}
var inst = Equity{}
var ex = testExchangeClient{}
const N_ORDERS = 1000000
b.ResetTimer()
b.N = N_ORDERS
for i:=0;i<N_ORDERS;i++ {
var o1 = LimitOrder(inst, Buy, NewDecimal("100"), NewDecimal("10"))
o1.ExchangeId = fmt.Sprint(i)
var s1 = sessionOrder{ex, o1, time.Now()}
ob.add(s1)
}
for i:=0;i<N_ORDERS;i++ {
var o1 = LimitOrder(inst, Sell, NewDecimal("100"), NewDecimal("10"))
o1.ExchangeId = "S"+fmt.Sprint(i)
var s1 = sessionOrder{ex, o1, time.Now()}
ob.add(s1)
}
}
Instead of setting b.N, is there a better way to get a “benchmark” for the
logical operation.
In this case, the number of operations is 2 * N_ORDERS, so I would like to time
the entire process and output in the benchmark format the time per “op”.
It seems to work setting b.N, but I’m sure this isn’t ideal.
In Java JMH, you have the ability to set the “number of operations” performed
during the test - I’m looking for something similar.
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