The behavior of Go 1.9 or 1.10 is even more weird.
They make the following code print false. ;D
package main
type T struct {}
func main() {
var a, b = &T{}, &T{}
println(a == b || a != b)
}
On Sunday, February 25, 2024 at 4:30:22 PM UTC+8 tapi...@gmail.com wrote:
> Absolutely a bug.
>
> On Thursday, February 22, 2024 at 6:55:49 PM UTC+8 Brien Colwell wrote:
>
>> I'm confused by this output. It appears that the interface of two
>> different pointers to an empty struct are equal. In all other cases,
>> interface equality seems to be the pointer equality. What's going on in the
>> empty struct case?
>>
>> ```
>> package main
>>
>> import "fmt"
>>
>> type Foo struct {
>> }
>>
>> func (self *Foo) Hello() {
>> }
>>
>> type FooWithValue struct {
>> A int
>> }
>>
>> func (self *FooWithValue) Hello() {
>> }
>>
>> type Bar interface {
>> Hello()
>> }
>>
>> func main() {
>> a := &Foo{}
>> b := &Foo{}
>> fmt.Printf("%t\n", *a == *b)
>> fmt.Printf("%t\n", a == b)
>> fmt.Printf("%t\n", Bar(a) == Bar(b))
>>
>> c := &FooWithValue{A: 1}
>> d := &FooWithValue{A: 1}
>> fmt.Printf("%t\n", *c == *d)
>> fmt.Printf("%t\n", c == d)
>> fmt.Printf("%t\n", Bar(c) == Bar(d))
>> }
>> ```
>>
>> Prints (emphasis added on the strange case):
>>
>> ```
>> true
>> false
>> **true**
>> true
>> false
>> false
>> ```
>>
>>
>>
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