I'm not sure what you mean. The `yield` function does exactly the same as
Python's `yield` statement and in fact, that's part of why the name was
chosen.
Compare Python:
def vals(a):
for v in a:
yield v
for x in vals([1,2,3]):
print(x)
With Go:
func vals[T any](s []T) iter.Seq[T] {
return func(yield func(T) bool) {
for _, v := range s {
if !yield(v) { return }
}
}
}
func main() {
for v := range vals([]int{1,2,3}) {
fmt.Println(v)
}
}
Sure, there is a little bit more ceremony involved, as you need things to
be typed and need to return a closure. But ultimately, the generating
function (in Go, the closure) calls yield to… yield a value.
On Wed, Feb 7, 2024 at 4:43 PM mspre...@gmail.com <mspreitz...@gmail.com>
wrote:
> The go language is getting better and better for functional programming,
> and I am here for it. I have enjoyed using APL, Scheme, Python. I was
> excited to see https://go.dev/wiki/RangefuncExperiment . However, I am
> puzzled by the choice to name the function parameter that _receives_ a
> Seq's values "yield". That func does the _complement_ to "yield", it
> _receives_ the value. Compare with Python's "yield" statement, which
> _provides_ the value. Couldn't we call the func parameter that receives a
> Seq's values something like "receive" or "consume"?
>
> Thanks,
> Mike
>
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