Yesterday, I came up with the same question and found this:
"github.com/lmittmann/tint"
(This solution still uses os.Stdout, but I think this can do what you need.)
An example:
logOptions := &tint.Options{
NoColor: true,
Level: slog.LevelError,
TimeFormat: time.DateTime,
}
logHandler := tint.NewHandler(os.Stdout, logOptions)
logger := slog.New(logHandler)
slog.SetDefault(logger)
slog.Info("this does not show")
slog.Debug("this debug info does not show")
logOptions.Level = slog.LevelInfo
slog.Info("this is now visible")
slog.Debug("this debug info still does not show")
logOptions.Level = slog.LevelDebug
slog.Info("this is still visible")
slog.Debug("this debug info also shows")
Op dinsdag 29 augustus 2023 om 03:00:01 UTC+2 schreef Mike Schinkel:
> Hi Tamás,
>
> Have you actually tried that and gotten it to work? It does not compile
> for me but this does (note method call vs. property reference):
>
> slog.SetDefault(slog.New(myHandler{Handler:slog.Default().Handler()}))
>
> However, when delegating the Handle() method it seems to cause an infinite
> loop:
>
> func (m MyHandler) Handle(ctx context.Context, r slog.Record) error {
> return m.Handler.Handle(ctx, r)
> }
>
> See https://goplay.tools/snippet/qw07m0YflLd
>
> I know about this because just this past weekend I was trying to write a
> TeeHandler to output the default to the screen and JSON to a file just this
> past weekend and ran into an infinite loop problem with the default
> handler.
>
> I tried my best to figure out why it needed to be structured the way it was
> in that it seems to call itself recursively. I wanted to post a question to
> this list to see if there was a workaround, or if not to see if there might
> be interest in allowing it to work, but I could not get my head around it
> so
> eventually gave up and just used the TextHandler instead.
>
> Shame though. It would be nice to be able to reuse the default handler but
> AFACT it is not possible (though if I am wrong I would love for someone to
> show me how to get it to work.)
>
> -Mike
>
>
> On Monday, August 28, 2023 at 12:50:50 PM UTC-4 Tamás Gulácsi wrote:
>
> slog.SetDefault(slog.New(myHandler{Handler:slog.Default().Handler}))
>
> vl...@mailbox.org a következőt írta (2023. augusztus 28., hétfő, 15:06:37
> UTC+2):
>
> Hi,
>
> When reading trough the log/slog documentation, it seems one can create
> a logger with a different handler, which is either NewTextHandler or
> NewJSONHandler.
>
> Why can't I configure the defaultHandler? Let's say I want my logger to
> behave exactly like the defaultHandler, but output to a logfile or
> Stdout instead.
>
> The defaultHandler's output is different compared to the NewTextHandler:
>
> slog.Info("ok"), gives me:
>
> INFO ok
>
> The NextTextHandler gives me:
>
> level=INFO msg="ok"
>
>
> Regards,
>
>
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