Thanks *Sean!!*
That makes sense for me!
But i guess I must import with an alias as import without an alias doesn't
works, right?
<user>@<machine>:<the_project_folder>/cmd$ go build .
# a_module_path/cmd
./main.go:4:2: imported and not used: "a_module_path" as util
./main.go:9:14: undefined: a_module_path
main.go
package main
import (
"a_module_path"
"fmt"
)
func main() {
fmt.Println(a_module_path.Abs(-2))
}
I mean... i'm actually importing it without utill.. so the message kind of
confuse me.
Thanks again.
El sábado, 15 de abril de 2023 a las 16:34:01 UTC-3, Sean Liao escribió:
> import "a_module_path"
>
> optionally rename it to make it clearer
>
> import util "a_module_path"
>
> - sean
>
> On Sat, Apr 15, 2023, 20:31 Victor Giordano <vituc...@gmail.com> wrote:
>
>> Hi there!
>>
>> I was playing a little bit with modules and packages, regarding making
>> projects.
>> And I'm struggling to use a package (non-main) declared in the root
>> directory.. allow me to show an example:
>>
>> This scenario, I have project somewhere on my file system
>> .
>> ├── cmd
>> │ └── main.go
>> ├── go.mod
>> └── util.go
>>
>> *go.mod*
>> module a_module_path
>>
>> go 1.19
>>
>>
>> *util.go*
>> package util
>>
>> func Abs(x int) int {
>> if x < 0 {
>> return -x
>> } else {
>> return x
>> }
>> }
>>
>> And the problem appears when I try to use the package util (in the root
>> directory of the module) within another package of the module...
>>
>> *cmd/main.go*
>> package main
>>
>> import (
>> "fmt"
>> "a_module_path/util" // this doesn't works
>> "a_module_path/../util" // this attemp neither (and as relative import
>> paths are not supported in module mode i guess is a no-go)
>> )
>>
>> func main() {
>> fmt.Println(util.Abs(-2))
>> }
>>
>> The question, as you may predict, is *¿If there any way to make this
>> work?*
>> *I do not want to create a folder named util (or whatever) and place
>> there the util package.*
>>
>> Thanks for the reading and the patience!
>> Keep rocking code!
>>
>> --
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