If you see `foo.bar()` it is definitely a method, as a package-scoped `bar` function would not be exported so it would not be visible in other packages. If, on the other hand, you see `foo.Bar()`, there is no easy way to tell. You have to know if `foo` is a variable or a package in the given scope.
On Tue, Apr 4, 2023 at 7:20 AM joseph.p...@gmail.com < joseph.p.mcguc...@gmail.com> wrote: > When I’m reading go source and I see something like foo.bar(), my brain > stutters for a second while I’m trying to determine if this is a reference > to a package function or a receiver/method. Is there an easy way to make > this determination? > > Thanks > > -- > You received this message because you are subscribed to the Google Groups > "golang-nuts" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to golang-nuts+unsubscr...@googlegroups.com. > To view this discussion on the web visit > https://groups.google.com/d/msgid/golang-nuts/e33c9734-4d83-4e21-9a95-b23be5e5a9bcn%40googlegroups.com > <https://groups.google.com/d/msgid/golang-nuts/e33c9734-4d83-4e21-9a95-b23be5e5a9bcn%40googlegroups.com?utm_medium=email&utm_source=footer> > . > -- You received this message because you are subscribed to the Google Groups "golang-nuts" group. To unsubscribe from this group and stop receiving emails from it, send an email to golang-nuts+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/golang-nuts/CAEkBMfGP9yVmrNJqv9-5A%2Bir21bLd%3DS54OFXS%2Bej22TF__6xcw%40mail.gmail.com.
